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122534531113 is a prime number
BaseRepresentation
bin111001000011110100…
…0001001000000101001
3102201021122100010120011
41302013220021000221
54001422314443423
6132142552131521
711565343220641
oct1620750110051
9381248303504
10122534531113
1147a6a603935
121b8b8696ba1
13b72a317017
145d05bc5521
1532c2752b0d
hex1c87a09029

122534531113 has 2 divisors, whose sum is σ = 122534531114. Its totient is φ = 122534531112.

The previous prime is 122534531099. The next prime is 122534531117. The reversal of 122534531113 is 311135435221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122382428224 + 152102889 = 349832^2 + 12333^2 .

It is a cyclic number.

It is not a de Polignac number, because 122534531113 - 217 = 122534400041 is a prime.

It is a super-2 number, since 2×1225345311132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122534531117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61267265556 + 61267265557.

It is an arithmetic number, because the mean of its divisors is an integer number (61267265557).

Almost surely, 2122534531113 is an apocalyptic number.

It is an amenable number.

122534531113 is a deficient number, since it is larger than the sum of its proper divisors (1).

122534531113 is an equidigital number, since it uses as much as digits as its factorization.

122534531113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10800, while the sum is 31.

Adding to 122534531113 its reverse (311135435221), we get a palindrome (433669966334).

The spelling of 122534531113 in words is "one hundred twenty-two billion, five hundred thirty-four million, five hundred thirty-one thousand, one hundred thirteen".