1225404876383 has 4 divisors (see below), whose sum is σ = 1225553978760. Its totient is φ = 1225255774008.

The previous prime is 1225404876341. The next prime is 1225404876419. The reversal of 1225404876383 is 3836784045221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1225404876383 - 2⁸ = 1225404876127 is a prime.

It is a super-2 number, since 2×1225404876383² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1225404876323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74538860 + ... + 74555297.

It is an arithmetic number, because the mean of its divisors is an integer number (306388494690).

Almost surely, 2^{1225404876383} is an apocalyptic number.

1225404876383 is a deficient number, since it is larger than the sum of its proper divisors (149102377).

1225404876383 is an equidigital number, since it uses as much as digits as its factorization.

1225404876383 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149102376.

The product of its (nonzero) digits is 7741440, while the sum is 53.

The spelling of 1225404876383 in words is "one trillion, two hundred twenty-five billion, four hundred four million, eight hundred seventy-six thousand, three hundred eighty-three".