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12254164613641 is a prime number
BaseRepresentation
bin1011001001010010010100…
…1000001111101000001001
31121101111010210122020211101
42302110211020033220021
53101233012120114031
642021252511501401
72403222423412006
oct262244510175011
947344123566741
1012254164613641
1139a4a64505a05
12145ab32b27861
136ab7415178b2
143051675548ad
15163b5b679361
hexb252520fa09

12254164613641 has 2 divisors, whose sum is σ = 12254164613642. Its totient is φ = 12254164613640.

The previous prime is 12254164613623. The next prime is 12254164613651. The reversal of 12254164613641 is 14631646145221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9127619228025 + 3126545385616 = 3021195^2 + 1768204^2 .

It is a cyclic number.

It is not a de Polignac number, because 12254164613641 - 25 = 12254164613609 is a prime.

It is a super-2 number, since 2×122541646136412 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12254164613591 and 12254164613600.

It is not a weakly prime, because it can be changed into another prime (12254164613651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6127082306820 + 6127082306821.

It is an arithmetic number, because the mean of its divisors is an integer number (6127082306821).

Almost surely, 212254164613641 is an apocalyptic number.

It is an amenable number.

12254164613641 is a deficient number, since it is larger than the sum of its proper divisors (1).

12254164613641 is an equidigital number, since it uses as much as digits as its factorization.

12254164613641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 829440, while the sum is 46.

The spelling of 12254164613641 in words is "twelve trillion, two hundred fifty-four billion, one hundred sixty-four million, six hundred thirteen thousand, six hundred forty-one".