Base | Representation |
---|---|
bin | 10001110101010110111… |
… | …000011011010110110111 |
3 | 11100011021211022200222100 |
4 | 101311112320123112313 |
5 | 130034332431441210 |
6 | 2334555253433143 |
7 | 154353416163360 |
oct | 21652670332667 |
9 | 4304254280870 |
10 | 1225523312055 |
11 | 432817a62219 |
12 | 17962133b7b3 |
13 | 8b749379113 |
14 | 4345c1b4b67 |
15 | 21d2a7cd5c0 |
hex | 11d56e1b5b7 |
1225523312055 has 48 divisors (see below), whose sum is σ = 2430380519424. Its totient is φ = 559621414080.
The previous prime is 1225523312023. The next prime is 1225523312137. The reversal of 1225523312055 is 5502133255221.
1225523312055 is a `hidden beast` number, since 1 + 2 + 2 + 5 + 523 + 3 + 120 + 5 + 5 = 666.
It is not a de Polignac number, because 1225523312055 - 25 = 1225523312023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1859031 + ... + 2430440.
It is an arithmetic number, because the mean of its divisors is an integer number (50632927488).
Almost surely, 21225523312055 is an apocalyptic number.
1225523312055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1225523312055 is a deficient number, since it is larger than the sum of its proper divisors (1204857207369).
1225523312055 is a wasteful number, since it uses less digits than its factorization.
1225523312055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4290396 (or 4290393 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 1225523312055 its reverse (5502133255221), we get a palindrome (6727656567276).
The spelling of 1225523312055 in words is "one trillion, two hundred twenty-five billion, five hundred twenty-three million, three hundred twelve thousand, fifty-five".
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