Base | Representation |
---|---|
bin | 1011001001011001100011… |
… | …0110000101101011100101 |
3 | 1121101200011002201110211210 |
4 | 2302112120312011223211 |
5 | 3101301001114330430 |
6 | 42022213302422033 |
7 | 2403321506130456 |
oct | 262263066055345 |
9 | 47350132643753 |
10 | 12256106011365 |
11 | 39a5870366837 |
12 | 145b395131919 |
13 | 6ab9907b4248 |
14 | 3052ad31712d |
15 | 163c21d132b0 |
hex | b2598d85ae5 |
12256106011365 has 32 divisors (see below), whose sum is σ = 19688667255936. Its totient is φ = 6510292704000.
The previous prime is 12256106011333. The next prime is 12256106011403. The reversal of 12256106011365 is 56311060165221.
12256106011365 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12256106011365 - 25 = 12256106011333 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 132922419 + ... + 133014591.
It is an arithmetic number, because the mean of its divisors is an integer number (615270851748).
Almost surely, 212256106011365 is an apocalyptic number.
12256106011365 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12256106011365 is a deficient number, since it is larger than the sum of its proper divisors (7432561244571).
12256106011365 is a wasteful number, since it uses less digits than its factorization.
12256106011365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127749.
The product of its (nonzero) digits is 64800, while the sum is 39.
Adding to 12256106011365 its reverse (56311060165221), we get a palindrome (68567166176586).
The spelling of 12256106011365 in words is "twelve trillion, two hundred fifty-six billion, one hundred six million, eleven thousand, three hundred sixty-five".
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