Base | Representation |
---|---|
bin | 10110111001011000… |
… | …01000111000000001 |
3 | 1011201200111100001011 |
4 | 23130230020320001 |
5 | 200133334232201 |
6 | 5351434440521 |
7 | 613422315301 |
oct | 133454107001 |
9 | 34650440034 |
10 | 12292492801 |
11 | 5238878866 |
12 | 2470893141 |
13 | 120b9345a4 |
14 | 8487d9601 |
15 | 4be29a151 |
hex | 2dcb08e01 |
12292492801 has 2 divisors, whose sum is σ = 12292492802. Its totient is φ = 12292492800.
The previous prime is 12292492789. The next prime is 12292492811. The reversal of 12292492801 is 10829429221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12110782401 + 181710400 = 110049^2 + 13480^2 .
It is a cyclic number.
It is not a de Polignac number, because 12292492801 - 225 = 12258938369 is a prime.
It is a super-3 number, since 3×122924928013 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12292492811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6146246400 + 6146246401.
It is an arithmetic number, because the mean of its divisors is an integer number (6146246401).
Almost surely, 212292492801 is an apocalyptic number.
It is an amenable number.
12292492801 is a deficient number, since it is larger than the sum of its proper divisors (1).
12292492801 is an equidigital number, since it uses as much as digits as its factorization.
12292492801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 12292492801 in words is "twelve billion, two hundred ninety-two million, four hundred ninety-two thousand, eight hundred one".
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