Base | Representation |
---|---|
bin | 111001010000100111… |
… | …0111001110001000101 |
3 | 102202101120200122102102 |
4 | 1302201032321301011 |
5 | 4003312303411233 |
6 | 132253335521445 |
7 | 11612110540346 |
oct | 1624116716105 |
9 | 382346618372 |
10 | 122964122693 |
11 | 481700503a5 |
12 | 1b9b8529285 |
13 | b798319719 |
14 | 5d46c900cd |
15 | 32ea30e1e8 |
hex | 1ca13b9c45 |
122964122693 has 4 divisors (see below), whose sum is σ = 126930707328. Its totient is φ = 118997538060.
The previous prime is 122964122683. The next prime is 122964122719. The reversal of 122964122693 is 396221469221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 396221469221 = 6047 ⋅65523643.
It is not a de Polignac number, because 122964122693 - 210 = 122964121669 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122964122683) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1983292271 + ... + 1983292332.
It is an arithmetic number, because the mean of its divisors is an integer number (31732676832).
Almost surely, 2122964122693 is an apocalyptic number.
It is an amenable number.
122964122693 is a deficient number, since it is larger than the sum of its proper divisors (3966584635).
122964122693 is an equidigital number, since it uses as much as digits as its factorization.
122964122693 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3966584634.
The product of its digits is 559872, while the sum is 47.
The spelling of 122964122693 in words is "one hundred twenty-two billion, nine hundred sixty-four million, one hundred twenty-two thousand, six hundred ninety-three".
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