Base | Representation |
---|---|
bin | 11011111101111000110011… |
… | …000100000111111100111011 |
3 | 121010111200211112221012200001 |
4 | 123331320303010013330323 |
5 | 112110213231304021021 |
6 | 1113333251341453431 |
7 | 34623315613503103 |
oct | 3375706304077473 |
9 | 533450745835601 |
10 | 123000130142011 |
11 | 36212075949571 |
12 | 119662ba871277 |
13 | 5382b29bc4b85 |
14 | 2253349362203 |
15 | e347b0505091 |
hex | 6fde33107f3b |
123000130142011 has 2 divisors, whose sum is σ = 123000130142012. Its totient is φ = 123000130142010.
The previous prime is 123000130141937. The next prime is 123000130142017. The reversal of 123000130142011 is 110241031000321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123000130142011 - 229 = 122999593271099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 123000130142011.
It is not a weakly prime, because it can be changed into another prime (123000130142017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500065071005 + 61500065071006.
It is an arithmetic number, because the mean of its divisors is an integer number (61500065071006).
Almost surely, 2123000130142011 is an apocalyptic number.
123000130142011 is a deficient number, since it is larger than the sum of its proper divisors (1).
123000130142011 is an equidigital number, since it uses as much as digits as its factorization.
123000130142011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 123000130142011 its reverse (110241031000321), we get a palindrome (233241161142332).
The spelling of 123000130142011 in words is "one hundred twenty-three trillion, one hundred thirty million, one hundred forty-two thousand, eleven".
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