Base | Representation |
---|---|
bin | 111001010001101100… |
… | …1000110111010100111 |
3 | 102202111002212022021021 |
4 | 1302203121012322213 |
5 | 4003401042234143 |
6 | 132301112232011 |
7 | 11613030513364 |
oct | 1624331067247 |
9 | 382432768237 |
10 | 123000352423 |
11 | 48189546323 |
12 | 1ba0869b607 |
13 | b7a2993130 |
14 | 5d4ba0146b |
15 | 32ed5b8ced |
hex | 1ca3646ea7 |
123000352423 has 4 divisors (see below), whose sum is σ = 132461918008. Its totient is φ = 113538786840.
The previous prime is 123000352411. The next prime is 123000352439. The reversal of 123000352423 is 324253000321.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 123000352423 - 221 = 122998255271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123000352463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4730782773 + ... + 4730782798.
It is an arithmetic number, because the mean of its divisors is an integer number (33115479502).
Almost surely, 2123000352423 is an apocalyptic number.
123000352423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
123000352423 is a deficient number, since it is larger than the sum of its proper divisors (9461565585).
123000352423 is an equidigital number, since it uses as much as digits as its factorization.
123000352423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9461565584.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 123000352423 its reverse (324253000321), we get a palindrome (447253352744).
The spelling of 123000352423 in words is "one hundred twenty-three billion, three hundred fifty-two thousand, four hundred twenty-three".
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