Base | Representation |
---|---|
bin | 10110111010010001… |
… | …11010010101110001 |
3 | 1011202012200112121012 |
4 | 23131020322111301 |
5 | 200142302113231 |
6 | 5352304240305 |
7 | 613543401431 |
oct | 133510722561 |
9 | 34665615535 |
10 | 12300035441 |
11 | 524205a751 |
12 | 2473310095 |
13 | 12103757a5 |
14 | 8498002c1 |
15 | 4bec89e2b |
hex | 2dd23a571 |
12300035441 has 2 divisors, whose sum is σ = 12300035442. Its totient is φ = 12300035440.
The previous prime is 12300035413. The next prime is 12300035507. The reversal of 12300035441 is 14453000321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8881177600 + 3418857841 = 94240^2 + 58471^2 .
It is an emirp because it is prime and its reverse (14453000321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12300035441 - 222 = 12295841137 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (12300035401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150017720 + 6150017721.
It is an arithmetic number, because the mean of its divisors is an integer number (6150017721).
Almost surely, 212300035441 is an apocalyptic number.
It is an amenable number.
12300035441 is a deficient number, since it is larger than the sum of its proper divisors (1).
12300035441 is an equidigital number, since it uses as much as digits as its factorization.
12300035441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12300035441 its reverse (14453000321), we get a palindrome (26753035762).
The spelling of 12300035441 in words is "twelve billion, three hundred million, thirty-five thousand, four hundred forty-one".
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