Base | Representation |
---|---|
bin | 11011111101111001000110… |
… | …010101110001001011101011 |
3 | 121010111201200002110020200112 |
4 | 123331321012111301023223 |
5 | 112110214412101100233 |
6 | 1113333343413124535 |
7 | 34623326621341142 |
oct | 3375710625611353 |
9 | 533451602406615 |
10 | 123000453534443 |
11 | 36212221450041 |
12 | 1196638b02974b |
13 | 5382b7bbc3244 |
14 | 225337a2a4759 |
15 | e347cdad5048 |
hex | 6fde465712eb |
123000453534443 has 2 divisors, whose sum is σ = 123000453534444. Its totient is φ = 123000453534442.
The previous prime is 123000453534419. The next prime is 123000453534473. The reversal of 123000453534443 is 344435354000321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123000453534443 - 242 = 118602407023339 is a prime.
It is a super-2 number, since 2×1230004535344432 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 123000453534443.
It is not a weakly prime, because it can be changed into another prime (123000453534473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500226767221 + 61500226767222.
It is an arithmetic number, because the mean of its divisors is an integer number (61500226767222).
Almost surely, 2123000453534443 is an apocalyptic number.
123000453534443 is a deficient number, since it is larger than the sum of its proper divisors (1).
123000453534443 is an equidigital number, since it uses as much as digits as its factorization.
123000453534443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 41.
The spelling of 123000453534443 in words is "one hundred twenty-three trillion, four hundred fifty-three million, five hundred thirty-four thousand, four hundred forty-three".
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