Base | Representation |
---|---|
bin | 10001111001100010011… |
… | …011100100010110101011 |
3 | 11100120212122122201222102 |
4 | 101321202123210112223 |
5 | 130123031040244434 |
6 | 2341020522444015 |
7 | 154602562560515 |
oct | 21714233442653 |
9 | 4316778581872 |
10 | 1230012040619 |
11 | 43471080444a |
12 | 17a47466360b |
13 | 8bcb330741b |
14 | 437663c8bb5 |
15 | 21ede8e207e |
hex | 11e626e45ab |
1230012040619 has 2 divisors, whose sum is σ = 1230012040620. Its totient is φ = 1230012040618.
The previous prime is 1230012040577. The next prime is 1230012040639. The reversal of 1230012040619 is 9160402100321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1230012040619 - 28 = 1230012040363 is a prime.
It is a super-2 number, since 2×12300120406192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1230012040591 and 1230012040600.
It is not a weakly prime, because it can be changed into another prime (1230012040639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615006020309 + 615006020310.
It is an arithmetic number, because the mean of its divisors is an integer number (615006020310).
Almost surely, 21230012040619 is an apocalyptic number.
1230012040619 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230012040619 is an equidigital number, since it uses as much as digits as its factorization.
1230012040619 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 1230012040619 in words is "one trillion, two hundred thirty billion, twelve million, forty thousand, six hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •