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1230012041113 is a prime number
BaseRepresentation
bin10001111001100010011…
…011100100011110011001
311100120212122122202122201
4101321202123210132121
5130123031040303423
62341020522450201
7154602562562122
oct21714233443631
94316778582581
101230012041113
11434710804859
1217a474663961
138bcb330770b
14437663c9049
1521ede8e22ad
hex11e626e4799

1230012041113 has 2 divisors, whose sum is σ = 1230012041114. Its totient is φ = 1230012041112.

The previous prime is 1230012041101. The next prime is 1230012041173. The reversal of 1230012041113 is 3111402100321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1070877268224 + 159134772889 = 1034832^2 + 398917^2 .

It is a cyclic number.

It is not a de Polignac number, because 1230012041113 - 233 = 1221422106521 is a prime.

It is not a weakly prime, because it can be changed into another prime (1230012041173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615006020556 + 615006020557.

It is an arithmetic number, because the mean of its divisors is an integer number (615006020557).

Almost surely, 21230012041113 is an apocalyptic number.

It is an amenable number.

1230012041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230012041113 is an equidigital number, since it uses as much as digits as its factorization.

1230012041113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1230012041113 its reverse (3111402100321), we get a palindrome (4341414141434).

The spelling of 1230012041113 in words is "one trillion, two hundred thirty billion, twelve million, forty-one thousand, one hundred thirteen".