Base | Representation |
---|---|
bin | 10001111001100010011… |
… | …011100100011110101011 |
3 | 11100120212122122202200101 |
4 | 101321202123210132223 |
5 | 130123031040304011 |
6 | 2341020522450231 |
7 | 154602562562146 |
oct | 21714233443653 |
9 | 4316778582611 |
10 | 1230012041131 |
11 | 434710804875 |
12 | 17a474663977 |
13 | 8bcb3307723 |
14 | 437663c905d |
15 | 21ede8e22c1 |
hex | 11e626e47ab |
1230012041131 has 36 divisors (see below), whose sum is σ = 1370249510448. Its totient is φ = 1103771341728.
The previous prime is 1230012041113. The next prime is 1230012041173. The reversal of 1230012041131 is 1311402100321.
It is not a de Polignac number, because 1230012041131 - 29 = 1230012040619 is a prime.
It is a super-2 number, since 2×12300120411312 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1230012041099 and 1230012041108.
It is not an unprimeable number, because it can be changed into a prime (1230012041101) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 19638541 + ... + 19701073.
Almost surely, 21230012041131 is an apocalyptic number.
1230012041131 is a deficient number, since it is larger than the sum of its proper divisors (140237469317).
1230012041131 is a wasteful number, since it uses less digits than its factorization.
1230012041131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62720 (or 62678 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1230012041131 its reverse (1311402100321), we get a palindrome (2541414141452).
The spelling of 1230012041131 in words is "one trillion, two hundred thirty billion, twelve million, forty-one thousand, one hundred thirty-one".
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