Base | Representation |
---|---|
bin | 10001111001100010011… |
… | …100010000001010000001 |
3 | 11100120212122222212002101 |
4 | 101321202130100022001 |
5 | 130123031112020113 |
6 | 2341020530350401 |
7 | 154602564235552 |
oct | 21714234201201 |
9 | 4316778885071 |
10 | 1230012220033 |
11 | 434710917223 |
12 | 17a47472b401 |
13 | 8bcb336ac9c |
14 | 43766434329 |
15 | 21ede92a2dd |
hex | 11e62710281 |
1230012220033 has 2 divisors, whose sum is σ = 1230012220034. Its totient is φ = 1230012220032.
The previous prime is 1230012220013. The next prime is 1230012220043. The reversal of 1230012220033 is 3300222100321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1138452722289 + 91559497744 = 1066983^2 + 302588^2 .
It is a cyclic number.
It is not a de Polignac number, because 1230012220033 - 233 = 1221422285441 is a prime.
It is a super-2 number, since 2×12300122200332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1230012220013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615006110016 + 615006110017.
It is an arithmetic number, because the mean of its divisors is an integer number (615006110017).
Almost surely, 21230012220033 is an apocalyptic number.
It is an amenable number.
1230012220033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230012220033 is an equidigital number, since it uses as much as digits as its factorization.
1230012220033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1230012220033 its reverse (3300222100321), we get a palindrome (4530234320354).
The spelling of 1230012220033 in words is "one trillion, two hundred thirty billion, twelve million, two hundred twenty thousand, thirty-three".
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