Base | Representation |
---|---|
bin | 11011111101111001111011… |
… | …111011001111011011001011 |
3 | 121010111210222202002222022101 |
4 | 123331321323323033123023 |
5 | 112110223232223100331 |
6 | 1113334012530134231 |
7 | 34623361116010051 |
oct | 3375717373173313 |
9 | 533453882088271 |
10 | 123001352550091 |
11 | 3621264296a884 |
12 | 119665a0121377 |
13 | 5382c93233872 |
14 | 22534238461d1 |
15 | e348329ba061 |
hex | 6fde7becf6cb |
123001352550091 has 2 divisors, whose sum is σ = 123001352550092. Its totient is φ = 123001352550090.
The previous prime is 123001352550077. The next prime is 123001352550103. The reversal of 123001352550091 is 190055253100321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123001352550091 - 219 = 123001352025803 is a prime.
It is a super-3 number, since 3×1230013525500913 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 123001352550091.
It is not a weakly prime, because it can be changed into another prime (123001352520091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500676275045 + 61500676275046.
It is an arithmetic number, because the mean of its divisors is an integer number (61500676275046).
Almost surely, 2123001352550091 is an apocalyptic number.
123001352550091 is a deficient number, since it is larger than the sum of its proper divisors (1).
123001352550091 is an equidigital number, since it uses as much as digits as its factorization.
123001352550091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 37.
The spelling of 123001352550091 in words is "one hundred twenty-three trillion, one billion, three hundred fifty-two million, five hundred fifty thousand, ninety-one".
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