Base | Representation |
---|---|
bin | 100100101010000… |
… | …1010110110110001 |
3 | 10011201111200212122 |
4 | 1021110022312301 |
5 | 10004341232423 |
6 | 322015404025 |
7 | 42324014063 |
oct | 11124126661 |
9 | 3151450778 |
10 | 1230024113 |
11 | 58135335a |
12 | 2a3b23615 |
13 | 167aa7426 |
14 | b9507733 |
15 | 72ebb8c8 |
hex | 4950adb1 |
1230024113 has 2 divisors, whose sum is σ = 1230024114. Its totient is φ = 1230024112.
The previous prime is 1230024101. The next prime is 1230024119. The reversal of 1230024113 is 3114200321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1216126129 + 13897984 = 34873^2 + 3728^2 .
It is a cyclic number.
It is not a de Polignac number, because 1230024113 - 210 = 1230023089 is a prime.
It is a super-2 number, since 2×12300241132 = 3025918637122873538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1230024091 and 1230024100.
It is not a weakly prime, because it can be changed into another prime (1230024119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615012056 + 615012057.
It is an arithmetic number, because the mean of its divisors is an integer number (615012057).
Almost surely, 21230024113 is an apocalyptic number.
It is an amenable number.
1230024113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230024113 is an equidigital number, since it uses as much as digits as its factorization.
1230024113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 1230024113 is about 35071.6996023860. The cubic root of 1230024113 is about 1071.4482711798.
Adding to 1230024113 its reverse (3114200321), we get a palindrome (4344224434).
The spelling of 1230024113 in words is "one billion, two hundred thirty million, twenty-four thousand, one hundred thirteen".
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