Base | Representation |
---|---|
bin | 11011111110000011000010… |
… | …001111000111100001100011 |
3 | 121010112202012121020112210011 |
4 | 123332003002033013201203 |
5 | 112110403234224202243 |
6 | 1113342310201345351 |
7 | 34624155164553562 |
oct | 3376030217074143 |
9 | 533482177215704 |
10 | 123011122100323 |
11 | 362167a6594536 |
12 | 11968467a98257 |
13 | 5383b8c265112 |
14 | 2253aad13bbd9 |
15 | e34c0550689d |
hex | 6fe0c23c7863 |
123011122100323 has 2 divisors, whose sum is σ = 123011122100324. Its totient is φ = 123011122100322.
The previous prime is 123011122100227. The next prime is 123011122100341. The reversal of 123011122100323 is 323001221110321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123011122100323 - 221 = 123011120003171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123011122100294 and 123011122100303.
It is not a weakly prime, because it can be changed into another prime (123011122100353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505561050161 + 61505561050162.
It is an arithmetic number, because the mean of its divisors is an integer number (61505561050162).
Almost surely, 2123011122100323 is an apocalyptic number.
123011122100323 is a deficient number, since it is larger than the sum of its proper divisors (1).
123011122100323 is an equidigital number, since it uses as much as digits as its factorization.
123011122100323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 123011122100323 its reverse (323001221110321), we get a palindrome (446012343210644).
The spelling of 123011122100323 in words is "one hundred twenty-three trillion, eleven billion, one hundred twenty-two million, one hundred thousand, three hundred twenty-three".
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