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12301113102067 is a prime number
BaseRepresentation
bin1011001100000001001101…
…1110100000111011110011
31121112222022201111120112001
42303000103132200323303
53103020134423231232
642055015304514431
72406504023110366
oct263002336407363
947488281446461
1012301113102067
113a12966725169
121468055a7ba17
136b2cb400896a
1430753c8b00dd
15164ea81a26e7
hexb30137a0ef3

12301113102067 has 2 divisors, whose sum is σ = 12301113102068. Its totient is φ = 12301113102066.

The previous prime is 12301113102059. The next prime is 12301113102149. The reversal of 12301113102067 is 76020131110321.

12301113102067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (76020131110321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12301113102067 - 23 = 12301113102059 is a prime.

It is not a weakly prime, because it can be changed into another prime (12301113162067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150556551033 + 6150556551034.

It is an arithmetic number, because the mean of its divisors is an integer number (6150556551034).

Almost surely, 212301113102067 is an apocalyptic number.

12301113102067 is a deficient number, since it is larger than the sum of its proper divisors (1).

12301113102067 is an equidigital number, since it uses as much as digits as its factorization.

12301113102067 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 12301113102067 its reverse (76020131110321), we get a palindrome (88321244212388).

The spelling of 12301113102067 in words is "twelve trillion, three hundred one billion, one hundred thirteen million, one hundred two thousand, sixty-seven".