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123011213153 is a prime number
BaseRepresentation
bin111001010010000001…
…0100010011101100001
3102202111212022002101112
41302210002202131201
54003411332310103
6132302141113105
711613222026333
oct1624402423541
9382455262345
10123011213153
1148194694134
121ba10258795
13b7a4cc66ba
145d4d22b453
1532ee511cd8
hex1ca40a2761

123011213153 has 2 divisors, whose sum is σ = 123011213154. Its totient is φ = 123011213152.

The previous prime is 123011213089. The next prime is 123011213167. The reversal of 123011213153 is 351312110321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122071974544 + 939238609 = 349388^2 + 30647^2 .

It is an emirp because it is prime and its reverse (351312110321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123011213153 - 26 = 123011213089 is a prime.

It is a super-3 number, since 3×1230112131533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (123011213173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505606576 + 61505606577.

It is an arithmetic number, because the mean of its divisors is an integer number (61505606577).

Almost surely, 2123011213153 is an apocalyptic number.

It is an amenable number.

123011213153 is a deficient number, since it is larger than the sum of its proper divisors (1).

123011213153 is an equidigital number, since it uses as much as digits as its factorization.

123011213153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 123011213153 its reverse (351312110321), we get a palindrome (474323323474).

The spelling of 123011213153 in words is "one hundred twenty-three billion, eleven million, two hundred thirteen thousand, one hundred fifty-three".