Base | Representation |
---|---|
bin | 11011111110000100010110… |
… | …110100111110100001001011 |
3 | 121010112212212111201220220110 |
4 | 123332010112310332201023 |
5 | 112110414141033423201 |
6 | 1113343103100125403 |
7 | 34624235306630310 |
oct | 3376042664764113 |
9 | 533485774656813 |
10 | 123012541311051 |
11 | 36217364704567 |
12 | 119687a3236863 |
13 | 53840572ab992 |
14 | 2253ba5810d07 |
15 | e34c89de36d6 |
hex | 6fe116d3e84b |
123012541311051 has 64 divisors (see below), whose sum is σ = 201249022279680. Its totient is φ = 65275809137280.
The previous prime is 123012541311043. The next prime is 123012541311053. The reversal of 123012541311051 is 150113145210321.
It is not a de Polignac number, because 123012541311051 - 23 = 123012541311043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (123012541311053) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7649035 + ... + 17450868.
It is an arithmetic number, because the mean of its divisors is an integer number (3144515973120).
Almost surely, 2123012541311051 is an apocalyptic number.
123012541311051 is a deficient number, since it is larger than the sum of its proper divisors (78236480968629).
123012541311051 is a wasteful number, since it uses less digits than its factorization.
123012541311051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25100176.
The product of its (nonzero) digits is 3600, while the sum is 30.
Adding to 123012541311051 its reverse (150113145210321), we get a palindrome (273125686521372).
The spelling of 123012541311051 in words is "one hundred twenty-three trillion, twelve billion, five hundred forty-one million, three hundred eleven thousand, fifty-one".
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