Base | Representation |
---|---|
bin | 11011111110000100111110… |
… | …001001101011110110100010 |
3 | 121010112221120111011012000221 |
4 | 123332010332021223312202 |
5 | 112110422013432113132 |
6 | 1113343252344433254 |
7 | 34624260540421441 |
oct | 3376047611536642 |
9 | 533487514135027 |
10 | 123013201051042 |
11 | 36217673055a25 |
12 | 1196894817882a |
13 | 5384130b93083 |
14 | 2253c292a8d58 |
15 | e34cc7cb1e97 |
hex | 6fe13e26bda2 |
123013201051042 has 4 divisors (see below), whose sum is σ = 184519801576566. Its totient is φ = 61506600525520.
The previous prime is 123013201050941. The next prime is 123013201051057. The reversal of 123013201051042 is 240150102310321.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 115506198359161 + 7507002691881 = 10747381^2 + 2739891^2 .
It is a super-2 number, since 2×1230132010510422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123013201050998 and 123013201051016.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30753300262759 + ... + 30753300262762.
Almost surely, 2123013201051042 is an apocalyptic number.
123013201051042 is a deficient number, since it is larger than the sum of its proper divisors (61506600525524).
123013201051042 is an equidigital number, since it uses as much as digits as its factorization.
123013201051042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61506600525523.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 123013201051042 its reverse (240150102310321), we get a palindrome (363163303361363).
The spelling of 123013201051042 in words is "one hundred twenty-three trillion, thirteen billion, two hundred one million, fifty-one thousand, forty-two".
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