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123013201051042 = 261506600525521
BaseRepresentation
bin11011111110000100111110…
…001001101011110110100010
3121010112221120111011012000221
4123332010332021223312202
5112110422013432113132
61113343252344433254
734624260540421441
oct3376047611536642
9533487514135027
10123013201051042
1136217673055a25
121196894817882a
135384130b93083
142253c292a8d58
15e34cc7cb1e97
hex6fe13e26bda2

123013201051042 has 4 divisors (see below), whose sum is σ = 184519801576566. Its totient is φ = 61506600525520.

The previous prime is 123013201050941. The next prime is 123013201051057. The reversal of 123013201051042 is 240150102310321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 115506198359161 + 7507002691881 = 10747381^2 + 2739891^2 .

It is a super-2 number, since 2×1230132010510422 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123013201050998 and 123013201051016.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30753300262759 + ... + 30753300262762.

Almost surely, 2123013201051042 is an apocalyptic number.

123013201051042 is a deficient number, since it is larger than the sum of its proper divisors (61506600525524).

123013201051042 is an equidigital number, since it uses as much as digits as its factorization.

123013201051042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61506600525523.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 123013201051042 its reverse (240150102310321), we get a palindrome (363163303361363).

The spelling of 123013201051042 in words is "one hundred twenty-three trillion, thirteen billion, two hundred one million, fifty-one thousand, forty-two".

Divisors: 1 2 61506600525521 123013201051042