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123013203024251 is a prime number
BaseRepresentation
bin11011111110000100111110…
…010001001101100101111011
3121010112221120121212102202202
4123332010332101031211323
5112110422014433234001
61113343252455020415
734624260563250311
oct3376047621154573
9533487517772682
10123013203024251
1136217674183481
121196894896a70b
135384131404257
142253c296600b1
15e34cc805196b
hex6fe13e44d97b

123013203024251 has 2 divisors, whose sum is σ = 123013203024252. Its totient is φ = 123013203024250.

The previous prime is 123013203024191. The next prime is 123013203024301. The reversal of 123013203024251 is 152420302310321.

It is a strong prime.

It is an emirp because it is prime and its reverse (152420302310321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123013203024251 is a prime.

It is a super-2 number, since 2×1230132030242512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123013203024851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506601512125 + 61506601512126.

It is an arithmetic number, because the mean of its divisors is an integer number (61506601512126).

Almost surely, 2123013203024251 is an apocalyptic number.

123013203024251 is a deficient number, since it is larger than the sum of its proper divisors (1).

123013203024251 is an equidigital number, since it uses as much as digits as its factorization.

123013203024251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 123013203024251 its reverse (152420302310321), we get a palindrome (275433505334572).

The spelling of 123013203024251 in words is "one hundred twenty-three trillion, thirteen billion, two hundred three million, twenty-four thousand, two hundred fifty-one".