Base | Representation |
---|---|
bin | 11011111110000100111110… |
… | …010001001101100101111011 |
3 | 121010112221120121212102202202 |
4 | 123332010332101031211323 |
5 | 112110422014433234001 |
6 | 1113343252455020415 |
7 | 34624260563250311 |
oct | 3376047621154573 |
9 | 533487517772682 |
10 | 123013203024251 |
11 | 36217674183481 |
12 | 1196894896a70b |
13 | 5384131404257 |
14 | 2253c296600b1 |
15 | e34cc805196b |
hex | 6fe13e44d97b |
123013203024251 has 2 divisors, whose sum is σ = 123013203024252. Its totient is φ = 123013203024250.
The previous prime is 123013203024191. The next prime is 123013203024301. The reversal of 123013203024251 is 152420302310321.
It is a strong prime.
It is an emirp because it is prime and its reverse (152420302310321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123013203024251 is a prime.
It is a super-2 number, since 2×1230132030242512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123013203024851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506601512125 + 61506601512126.
It is an arithmetic number, because the mean of its divisors is an integer number (61506601512126).
Almost surely, 2123013203024251 is an apocalyptic number.
123013203024251 is a deficient number, since it is larger than the sum of its proper divisors (1).
123013203024251 is an equidigital number, since it uses as much as digits as its factorization.
123013203024251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 123013203024251 its reverse (152420302310321), we get a palindrome (275433505334572).
The spelling of 123013203024251 in words is "one hundred twenty-three trillion, thirteen billion, two hundred three million, twenty-four thousand, two hundred fifty-one".
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