Base | Representation |
---|---|
bin | 10001111001101110001… |
… | …111111100111011100011 |
3 | 11100121101110202111002201 |
4 | 101321232033330323203 |
5 | 130123432320302042 |
6 | 2341052324354031 |
7 | 154610521130002 |
oct | 21715617747343 |
9 | 4317343674081 |
10 | 1230210322147 |
11 | 434802723284 |
12 | 17a50ab45917 |
13 | 8c01540c481 |
14 | 43784880c39 |
15 | 2200200c1b7 |
hex | 11e6e3fcee3 |
1230210322147 has 2 divisors, whose sum is σ = 1230210322148. Its totient is φ = 1230210322146.
The previous prime is 1230210322141. The next prime is 1230210322151. The reversal of 1230210322147 is 7412230120321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1230210322147 - 239 = 680454508259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1230210322141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615105161073 + 615105161074.
It is an arithmetic number, because the mean of its divisors is an integer number (615105161074).
Almost surely, 21230210322147 is an apocalyptic number.
1230210322147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230210322147 is an equidigital number, since it uses as much as digits as its factorization.
1230210322147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1230210322147 its reverse (7412230120321), we get a palindrome (8642440442468).
The spelling of 1230210322147 in words is "one trillion, two hundred thirty billion, two hundred ten million, three hundred twenty-two thousand, one hundred forty-seven".
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