Base | Representation |
---|---|
bin | 11011111110010100110101… |
… | …010110100111001101001011 |
3 | 121010121120112111100210120111 |
4 | 123332110311112213031023 |
5 | 112111211404212022443 |
6 | 1113355150421135151 |
7 | 34625432605315222 |
oct | 3376246526471513 |
9 | 533546474323514 |
10 | 123030233314123 |
11 | 36223913350303 |
12 | 1197010025a4b7 |
13 | 5385916771555 |
14 | 22549a3385cb9 |
15 | e3547320d69d |
hex | 6fe5355a734b |
123030233314123 has 2 divisors, whose sum is σ = 123030233314124. Its totient is φ = 123030233314122.
The previous prime is 123030233314099. The next prime is 123030233314129. The reversal of 123030233314123 is 321413332030321.
It is a strong prime.
It is an emirp because it is prime and its reverse (321413332030321) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123030233314123 is a prime.
It is not a weakly prime, because it can be changed into another prime (123030233314129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61515116657061 + 61515116657062.
It is an arithmetic number, because the mean of its divisors is an integer number (61515116657062).
Almost surely, 2123030233314123 is an apocalyptic number.
123030233314123 is a deficient number, since it is larger than the sum of its proper divisors (1).
123030233314123 is an equidigital number, since it uses as much as digits as its factorization.
123030233314123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 123030233314123 its reverse (321413332030321), we get a palindrome (444443565344444).
The spelling of 123030233314123 in words is "one hundred twenty-three trillion, thirty billion, two hundred thirty-three million, three hundred fourteen thousand, one hundred twenty-three".
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