Base | Representation |
---|---|
bin | 10110111010101000… |
… | …11010010100111001 |
3 | 1011202102100200212001 |
4 | 23131110122110321 |
5 | 200144040100131 |
6 | 5352453021001 |
7 | 613611125362 |
oct | 133524322471 |
9 | 34672320761 |
10 | 12303050041 |
11 | 5243829657 |
12 | 2474324761 |
13 | 1210b8c989 |
14 | 849d86b69 |
15 | 4c0183261 |
hex | 2dd51a539 |
12303050041 has 2 divisors, whose sum is σ = 12303050042. Its totient is φ = 12303050040.
The previous prime is 12303050029. The next prime is 12303050057. The reversal of 12303050041 is 14005030321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12016763641 + 286286400 = 109621^2 + 16920^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12303050041 is a prime.
It is a super-2 number, since 2×123030500412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12303050021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151525020 + 6151525021.
It is an arithmetic number, because the mean of its divisors is an integer number (6151525021).
Almost surely, 212303050041 is an apocalyptic number.
It is an amenable number.
12303050041 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303050041 is an equidigital number, since it uses as much as digits as its factorization.
12303050041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 19.
Adding to 12303050041 its reverse (14005030321), we get a palindrome (26308080362).
The spelling of 12303050041 in words is "twelve billion, three hundred three million, fifty thousand, forty-one".
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