Base | Representation |
---|---|
bin | 10110111010101001… |
… | …01001101110011001 |
3 | 1011202102110220101001 |
4 | 23131110221232121 |
5 | 200144044104423 |
6 | 5352454225001 |
7 | 613611510304 |
oct | 133524515631 |
9 | 34672426331 |
10 | 12303113113 |
11 | 5243871a85 |
12 | 2474355161 |
13 | 1210bb25b5 |
14 | 849da1b3b |
15 | 4c0196cad |
hex | 2dd529b99 |
12303113113 has 2 divisors, whose sum is σ = 12303113114. Its totient is φ = 12303113112.
The previous prime is 12303113107. The next prime is 12303113117. The reversal of 12303113113 is 31131130321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9651687049 + 2651426064 = 98243^2 + 51492^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12303113113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12303113117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151556556 + 6151556557.
It is an arithmetic number, because the mean of its divisors is an integer number (6151556557).
Almost surely, 212303113113 is an apocalyptic number.
It is an amenable number.
12303113113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12303113113 is an equidigital number, since it uses as much as digits as its factorization.
12303113113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 12303113113 its reverse (31131130321), we get a palindrome (43434243434).
The spelling of 12303113113 in words is "twelve billion, three hundred three million, one hundred thirteen thousand, one hundred thirteen".
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