123031401154130 has 128 divisors (see below), whose sum is σ = 256265746513920. Its totient is φ = 41656624289280.

The previous prime is 123031401154091. The next prime is 123031401154139. The reversal of 123031401154130 is 31451104130321.

It is a junction number, because it is equal to n+sod(n) for n = 123031401154093 and 123031401154102.

It is not an unprimeable number, because it can be changed into a prime (123031401154139) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7703417045 + ... + 7703433015.

It is an arithmetic number, because the mean of its divisors is an integer number (2002076144640).

Almost surely, 2^{123031401154130} is an apocalyptic number.

123031401154130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

123031401154130 is an abundant number, since it is smaller than the sum of its proper divisors (133234345359790).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123031401154130 is a wasteful number, since it uses less digits than its factorization.

123031401154130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20064.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 123031401154130 its reverse (31451104130321), we get a palindrome (154482505284451).

The spelling of 123031401154130 in words is "one hundred twenty-three trillion, thirty-one billion, four hundred one million, one hundred fifty-four thousand, one hundred thirty".