123031404133 has 4 divisors (see below), whose sum is σ = 134216077248. Its totient is φ = 111846731020.

The previous prime is 123031404113. The next prime is 123031404137. The reversal of 123031404133 is 331404130321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 123031404133 - 2¹⁷ = 123031273061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123031404098 and 123031404107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123031404137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5592336541 + ... + 5592336562.

It is an arithmetic number, because the mean of its divisors is an integer number (33554019312).

Almost surely, 2^123031404133 is an apocalyptic number.

It is an amenable number.

123031404133 is a deficient number, since it is larger than the sum of its proper divisors (11184673115).

123031404133 is a wasteful number, since it uses less digits than its factorization.

123031404133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11184673114.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 123031404133 its reverse (331404130321), we get a palindrome (454435534454).

The spelling of 123031404133 in words is "one hundred twenty-three billion, thirty-one million, four hundred four thousand, one hundred thirty-three".