Base | Representation |
---|---|
bin | 11011111110010110101101… |
… | …100011101010001100000011 |
3 | 121010121202202001010001200212 |
4 | 123332112231203222030003 |
5 | 112111230022000001011 |
6 | 1113400122501504335 |
7 | 34625533564004243 |
oct | 3376265543521403 |
9 | 533552661101625 |
10 | 123032250000131 |
11 | 3622475875435a |
12 | 119705837120ab |
13 | 5385b7850b794 |
14 | 2254b15145b23 |
15 | e355402ba08b |
hex | 6fe5ad8ea303 |
123032250000131 has 2 divisors, whose sum is σ = 123032250000132. Its totient is φ = 123032250000130.
The previous prime is 123032250000091. The next prime is 123032250000197. The reversal of 123032250000131 is 131000052230321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 123032250000131 - 218 = 123032249737987 is a prime.
It is a super-2 number, since 2×1230322500001312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123032250000097 and 123032250000106.
It is not a weakly prime, because it can be changed into another prime (123032280000131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61516125000065 + 61516125000066.
It is an arithmetic number, because the mean of its divisors is an integer number (61516125000066).
Almost surely, 2123032250000131 is an apocalyptic number.
123032250000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
123032250000131 is an equidigital number, since it uses as much as digits as its factorization.
123032250000131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
The spelling of 123032250000131 in words is "one hundred twenty-three trillion, thirty-two billion, two hundred fifty million, one hundred thirty-one", and thus it is an aban number.
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