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123033031033133 = 139464079310241
BaseRepresentation
bin11011111110010111011100…
…000111000100000100101101
3121010121211202110202122120002
4123332113130013010010231
5112111233121421030013
61113400332202034045
734625562126453344
oct3376273407040455
9533554673678502
10123033031033133
113622501960aa81
12119707611a8925
135385c712804a0
142254b8ab74b5b
15e35588b47358
hex6fe5dc1c412d

123033031033133 has 4 divisors (see below), whose sum is σ = 132497110343388. Its totient is φ = 113568951722880.

The previous prime is 123033031033091. The next prime is 123033031033169. The reversal of 123033031033133 is 331330130330321.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 55499117751529 + 67533913281604 = 7449773^2 + 8217902^2 .

It is a cyclic number.

It is not a de Polignac number, because 123033031033133 - 222 = 123033026838829 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 123033031033096 and 123033031033105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123033031033433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4732039655108 + ... + 4732039655133.

It is an arithmetic number, because the mean of its divisors is an integer number (33124277585847).

Almost surely, 2123033031033133 is an apocalyptic number.

123033031033133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

123033031033133 is a deficient number, since it is larger than the sum of its proper divisors (9464079310255).

123033031033133 is an equidigital number, since it uses as much as digits as its factorization.

123033031033133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9464079310254.

The product of its (nonzero) digits is 13122, while the sum is 29.

Adding to 123033031033133 its reverse (331330130330321), we get a palindrome (454363161363454).

The spelling of 123033031033133 in words is "one hundred twenty-three trillion, thirty-three billion, thirty-one million, thirty-three thousand, one hundred thirty-three".

Divisors: 1 13 9464079310241 123033031033133