Base | Representation |
---|---|
bin | 11011111110010111101110… |
… | …000000001001111101100101 |
3 | 121010121212112101121022201211 |
4 | 123332113232000021331211 |
5 | 112111234230242242013 |
6 | 1113400422043551421 |
7 | 34625602433106646 |
oct | 3376275600117545 |
9 | 533555471538654 |
10 | 123033331212133 |
11 | 36225162aa69a1 |
12 | 1197082582b571 |
13 | 5385cbb5118b4 |
14 | 2254bb89936cd |
15 | e355a518e23d |
hex | 6fe5ee009f65 |
123033331212133 has 4 divisors (see below), whose sum is σ = 123713073373708. Its totient is φ = 122353589050560.
The previous prime is 123033331212109. The next prime is 123033331212163. The reversal of 123033331212133 is 331212133330321.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 15772986996484 + 107260344215649 = 3971522^2 + 10356657^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123033331212133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 123033331212095 and 123033331212104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123033331212163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339871080516 + ... + 339871080877.
It is an arithmetic number, because the mean of its divisors is an integer number (30928268343427).
Almost surely, 2123033331212133 is an apocalyptic number.
It is an amenable number.
123033331212133 is a deficient number, since it is larger than the sum of its proper divisors (679742161575).
123033331212133 is an equidigital number, since it uses as much as digits as its factorization.
123033331212133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 679742161574.
The product of its (nonzero) digits is 17496, while the sum is 31.
Adding to 123033331212133 its reverse (331212133330321), we get a palindrome (454245464542454).
The spelling of 123033331212133 in words is "one hundred twenty-three trillion, thirty-three billion, three hundred thirty-one million, two hundred twelve thousand, one hundred thirty-three".
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