1230341140141 has 4 divisors (see below), whose sum is σ = 1230343443232. Its totient is φ = 1230338837052.

The previous prime is 1230341140129. The next prime is 1230341140159. The reversal of 1230341140141 is 1410411430321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1230341140141 - 2⁵ = 1230341140109 is a prime.

It is a super-2 number, since 2×1230341140141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1230341140241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111706 + ... + 1572628.

It is an arithmetic number, because the mean of its divisors is an integer number (307585860808).

Almost surely, 2^{1230341140141} is an apocalyptic number.

It is an amenable number.

1230341140141 is a deficient number, since it is larger than the sum of its proper divisors (2303091).

1230341140141 is an equidigital number, since it uses as much as digits as its factorization.

1230341140141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2303090.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1230341140141 its reverse (1410411430321), we get a palindrome (2640752570462).

The spelling of 1230341140141 in words is "one trillion, two hundred thirty billion, three hundred forty-one million, one hundred forty thousand, one hundred forty-one".