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12303420130003 is a prime number
BaseRepresentation
bin1011001100001001110011…
…1111001000001011010011
31121120012021111120201220011
42303002130333020023103
53103034401023130003
642100040240255351
72406615135402352
oct263023477101323
947505244521804
1012303420130003
113a1393aa06422
12146859a611557
136b3290c71952
143076bb04b999
151650909b146d
hexb309cfc82d3

12303420130003 has 2 divisors, whose sum is σ = 12303420130004. Its totient is φ = 12303420130002.

The previous prime is 12303420129971. The next prime is 12303420130073. The reversal of 12303420130003 is 30003102430321.

12303420130003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12303420130003 - 25 = 12303420129971 is a prime.

It is a super-3 number, since 3×123034201300033 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12303420130073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151710065001 + 6151710065002.

It is an arithmetic number, because the mean of its divisors is an integer number (6151710065002).

Almost surely, 212303420130003 is an apocalyptic number.

12303420130003 is a deficient number, since it is larger than the sum of its proper divisors (1).

12303420130003 is an equidigital number, since it uses as much as digits as its factorization.

12303420130003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 12303420130003 its reverse (30003102430321), we get a palindrome (42306522560324).

The spelling of 12303420130003 in words is "twelve trillion, three hundred three billion, four hundred twenty million, one hundred thirty thousand, three".