123050303400433 has 2 divisors, whose sum is σ = 123050303400434. Its totient is φ = 123050303400432.

The previous prime is 123050303400329. The next prime is 123050303400599. The reversal of 123050303400433 is 334004303050321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69366444137104 + 53683859263329 = 8328652^2 + 7326927^2 .

It is a cyclic number.

It is not a de Polignac number, because 123050303400433 - 2²⁵ = 123050269846001 is a prime.

It is a super-2 number, since 2×123050303400433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123050303400395 and 123050303400404.

It is not a weakly prime, because it can be changed into another prime (123050303401433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525151700216 + 61525151700217.

It is an arithmetic number, because the mean of its divisors is an integer number (61525151700217).

Almost surely, 2^{123050303400433} is an apocalyptic number.

It is an amenable number.

123050303400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123050303400433 is an equidigital number, since it uses as much as digits as its factorization.

123050303400433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 31.

Adding to 123050303400433 its reverse (334004303050321), we get a palindrome (457054606450754).

The spelling of 123050303400433 in words is "one hundred twenty-three trillion, fifty billion, three hundred three million, four hundred thousand, four hundred thirty-three".