Base | Representation |
---|---|
bin | 11011111110101000010111… |
… | …101110111010100110111111 |
3 | 121010200120200110222001222220 |
4 | 123332220113232322212333 |
5 | 112112032340032030210 |
6 | 1113412540202140423 |
7 | 34630104503411130 |
oct | 3376502756724677 |
9 | 533616613861886 |
10 | 123051211205055 |
11 | 362317a8872251 |
12 | 119741957b1713 |
13 | 53878aa914c73 |
14 | 22559d34a1c87 |
15 | e35c9ec3ec70 |
hex | 6fea17bba9bf |
123051211205055 has 32 divisors (see below), whose sum is σ = 225008467198464. Its totient is φ = 56251847730816.
The previous prime is 123051211204879. The next prime is 123051211205081. The reversal of 123051211205055 is 550502112150321.
It is not a de Polignac number, because 123051211205055 - 28 = 123051211204799 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52556892 + ... + 54848238.
It is an arithmetic number, because the mean of its divisors is an integer number (7031514599952).
Almost surely, 2123051211205055 is an apocalyptic number.
123051211205055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
123051211205055 is a deficient number, since it is larger than the sum of its proper divisors (101957255993409).
123051211205055 is a wasteful number, since it uses less digits than its factorization.
123051211205055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2802815.
The product of its (nonzero) digits is 15000, while the sum is 33.
Adding to 123051211205055 its reverse (550502112150321), we get a palindrome (673553323355376).
The spelling of 123051211205055 in words is "one hundred twenty-three trillion, fifty-one billion, two hundred eleven million, two hundred five thousand, fifty-five".
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