Base | Representation |
---|---|
bin | 111001010100101100… |
… | …1111001010011110011 |
3 | 102202202010200000111101 |
4 | 1302221121321103303 |
5 | 4004102403102011 |
6 | 132315114225231 |
7 | 11615364060226 |
oct | 1625131712363 |
9 | 382663600441 |
10 | 123101222131 |
11 | 48230481218 |
12 | 1ba36425217 |
13 | b7ba84c754 |
14 | 5d5b17b5bd |
15 | 33073912c1 |
hex | 1ca96794f3 |
123101222131 has 2 divisors, whose sum is σ = 123101222132. Its totient is φ = 123101222130.
The previous prime is 123101222087. The next prime is 123101222147. The reversal of 123101222131 is 131222101321.
It is a strong prime.
It is an emirp because it is prime and its reverse (131222101321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123101222131 - 27 = 123101222003 is a prime.
It is a super-2 number, since 2×1231012221312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123101222099 and 123101222108.
It is not a weakly prime, because it can be changed into another prime (123101222161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61550611065 + 61550611066.
It is an arithmetic number, because the mean of its divisors is an integer number (61550611066).
Almost surely, 2123101222131 is an apocalyptic number.
123101222131 is a deficient number, since it is larger than the sum of its proper divisors (1).
123101222131 is an equidigital number, since it uses as much as digits as its factorization.
123101222131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 123101222131 its reverse (131222101321), we get a palindrome (254323323452).
The spelling of 123101222131 in words is "one hundred twenty-three billion, one hundred one million, two hundred twenty-two thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •