12310130113333 has 4 divisors (see below), whose sum is σ = 13257063198988. Its totient is φ = 11363197027680.

The previous prime is 12310130113279. The next prime is 12310130113343. The reversal of 12310130113333 is 33331103101321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 872219641329 + 11437910472004 = 933927^2 + 3381998^2 .

It is a cyclic number.

It is not a de Polignac number, because 12310130113333 - 2²⁹ = 12309593242421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12310130113298 and 12310130113307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12310130113343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 473466542808 + ... + 473466542833.

It is an arithmetic number, because the mean of its divisors is an integer number (3314265799747).

Almost surely, 2^{12310130113333} is an apocalyptic number.

12310130113333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12310130113333 is a deficient number, since it is larger than the sum of its proper divisors (946933085655).

12310130113333 is an equidigital number, since it uses as much as digits as its factorization.

12310130113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 946933085654.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 12310130113333 its reverse (33331103101321), we get a palindrome (45641233214654).

The spelling of 12310130113333 in words is "twelve trillion, three hundred ten billion, one hundred thirty million, one hundred thirteen thousand, three hundred thirty-three".