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123101412013 = 472619178979
BaseRepresentation
bin111001010100101101…
…0100111101010101101
3102202202011000122222001
41302221122213222231
54004102430141023
6132315122252301
711615365510636
oct1625132475255
9382664018861
10123101412013
11482305a0948
121ba364b7091
13b7ba8b7cc8
145d5b1ca88d
1533073cc6ad
hex1ca96a7aad

123101412013 has 4 divisors (see below), whose sum is σ = 125720591040. Its totient is φ = 120482232988.

The previous prime is 123101411911. The next prime is 123101412017. The reversal of 123101412013 is 310214101321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123101412013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123101412017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1309589443 + ... + 1309589536.

It is an arithmetic number, because the mean of its divisors is an integer number (31430147760).

Almost surely, 2123101412013 is an apocalyptic number.

It is an amenable number.

123101412013 is a deficient number, since it is larger than the sum of its proper divisors (2619179027).

123101412013 is an equidigital number, since it uses as much as digits as its factorization.

123101412013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2619179026.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 123101412013 its reverse (310214101321), we get a palindrome (433315513334).

The spelling of 123101412013 in words is "one hundred twenty-three billion, one hundred one million, four hundred twelve thousand, thirteen".

Divisors: 1 47 2619178979 123101412013