Base | Representation |
---|---|
bin | 1011001100100011001001… |
… | …0011000100101100110011 |
3 | 1121120211211101222120210111 |
4 | 2303020302103010230303 |
5 | 3103142312323143443 |
6 | 42103123112042151 |
7 | 2410245505430455 |
oct | 263106223045463 |
9 | 47524741876714 |
10 | 12310220131123 |
11 | 3a1680a378962 |
12 | 1469977993357 |
13 | 6b3b059c0c55 |
14 | 307b641c62d5 |
15 | 16533c97169d |
hex | b32324c4b33 |
12310220131123 has 2 divisors, whose sum is σ = 12310220131124. Its totient is φ = 12310220131122.
The previous prime is 12310220131087. The next prime is 12310220131189. The reversal of 12310220131123 is 32113102201321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12310220131123 - 225 = 12310186576691 is a prime.
It is a super-2 number, since 2×123102201311232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12310220131094 and 12310220131103.
It is not a weakly prime, because it can be changed into another prime (12310220131723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155110065561 + 6155110065562.
It is an arithmetic number, because the mean of its divisors is an integer number (6155110065562).
Almost surely, 212310220131123 is an apocalyptic number.
12310220131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12310220131123 is an equidigital number, since it uses as much as digits as its factorization.
12310220131123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 12310220131123 its reverse (32113102201321), we get a palindrome (44423322332444).
The spelling of 12310220131123 in words is "twelve trillion, three hundred ten billion, two hundred twenty million, one hundred thirty-one thousand, one hundred twenty-three".
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