Base | Representation |
---|---|
bin | 10001111010011110101… |
… | …100011101010110001011 |
3 | 11100200111010010221112011 |
4 | 101322132230131112023 |
5 | 130132113403220243 |
6 | 2341305121200351 |
7 | 154636620466411 |
oct | 21723654352613 |
9 | 4320433127464 |
10 | 1231023101323 |
11 | 43508a4a2304 |
12 | 17a6b71900b7 |
13 | 8c114917bb2 |
14 | 438207b52b1 |
15 | 2204d55a89d |
hex | 11e9eb1d58b |
1231023101323 has 2 divisors, whose sum is σ = 1231023101324. Its totient is φ = 1231023101322.
The previous prime is 1231023101153. The next prime is 1231023101359. The reversal of 1231023101323 is 3231013201321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1231023101323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1231023101294 and 1231023101303.
It is not a weakly prime, because it can be changed into another prime (1231023101383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615511550661 + 615511550662.
It is an arithmetic number, because the mean of its divisors is an integer number (615511550662).
Almost surely, 21231023101323 is an apocalyptic number.
1231023101323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231023101323 is an equidigital number, since it uses as much as digits as its factorization.
1231023101323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1231023101323 its reverse (3231013201321), we get a palindrome (4462036302644).
The spelling of 1231023101323 in words is "one trillion, two hundred thirty-one billion, twenty-three million, one hundred one thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •