12311040121 has 2 divisors, whose sum is σ = 12311040122. Its totient is φ = 12311040120.

The previous prime is 12311040023. The next prime is 12311040149. The reversal of 12311040121 is 12104011321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10907713600 + 1403326521 = 104440^2 + 37461^2 .

It is an emirp because it is prime and its reverse (12104011321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12311040121 - 2²³ = 12302651513 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12311040095 and 12311040104.

It is not a weakly prime, because it can be changed into another prime (12311040151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155520060 + 6155520061.

It is an arithmetic number, because the mean of its divisors is an integer number (6155520061).

Almost surely, 2^12311040121 is an apocalyptic number.

It is an amenable number.

12311040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12311040121 is an equidigital number, since it uses as much as digits as its factorization.

12311040121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12311040121 its reverse (12104011321), we get a palindrome (24415051442).

The spelling of 12311040121 in words is "twelve billion, three hundred eleven million, forty thousand, one hundred twenty-one".