123110423413 has 4 divisors (see below), whose sum is σ = 123115387968. Its totient is φ = 123105458860.

The previous prime is 123110423407. The next prime is 123110423437. The reversal of 123110423413 is 314324011321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 314324011321 = 71 ⋅4427098751.

It is a cyclic number.

It is not a de Polignac number, because 123110423413 - 2³³ = 114520488821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123110424413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2444893 + ... + 2494738.

It is an arithmetic number, because the mean of its divisors is an integer number (30778846992).

Almost surely, 2^123110423413 is an apocalyptic number.

It is an amenable number.

123110423413 is a deficient number, since it is larger than the sum of its proper divisors (4964555).

123110423413 is an equidigital number, since it uses as much as digits as its factorization.

123110423413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4964554.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 123110423413 its reverse (314324011321), we get a palindrome (437434434734).

The spelling of 123110423413 in words is "one hundred twenty-three billion, one hundred ten million, four hundred twenty-three thousand, four hundred thirteen".