Base | Representation |
---|---|
bin | 1011001100100110100000… |
… | …0000001010011001110111 |
3 | 1121120221011012101202022010 |
4 | 2303021220000022121313 |
5 | 3103201134003042130 |
6 | 42103352335535303 |
7 | 2410310026053453 |
oct | 263115000123167 |
9 | 47527135352263 |
10 | 12311121143415 |
11 | 3a17131a31816 |
12 | 1469b8968a533 |
13 | 6b3c1a580313 |
14 | 307c0bb27663 |
15 | 165391aed0b0 |
hex | b326800a677 |
12311121143415 has 16 divisors (see below), whose sum is σ = 19698173134848. Its totient is φ = 6565804841376.
The previous prime is 12311121143383. The next prime is 12311121143423. The reversal of 12311121143415 is 51434112111321.
It is not a de Polignac number, because 12311121143415 - 25 = 12311121143383 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7094599 + ... + 8657688.
It is an arithmetic number, because the mean of its divisors is an integer number (1231135820928).
Almost surely, 212311121143415 is an apocalyptic number.
12311121143415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12311121143415 is a deficient number, since it is larger than the sum of its proper divisors (7387051991433).
12311121143415 is a wasteful number, since it uses less digits than its factorization.
12311121143415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15804398.
The product of its digits is 2880, while the sum is 30.
Adding to 12311121143415 its reverse (51434112111321), we get a palindrome (63745233254736).
The spelling of 12311121143415 in words is "twelve trillion, three hundred eleven billion, one hundred twenty-one million, one hundred forty-three thousand, four hundred fifteen".
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