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123113200151 = 131939795421
BaseRepresentation
bin111001010101000011…
…1100101101000010111
3102202202222012120020202
41302222013211220113
54004113434401101
6132320223051115
711615600635454
oct1625207455027
9382688176222
10123113200151
1148237212507
121ba3a440a9b
13b7c0184736
145d5c9b882b
15330845a36b
hex1caa1e5a17

123113200151 has 4 divisors (see below), whose sum is σ = 124052995704. Its totient is φ = 122173404600.

The previous prime is 123113200123. The next prime is 123113200219. The reversal of 123113200151 is 151002311321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123113200151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123113200121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469897580 + ... + 469897841.

It is an arithmetic number, because the mean of its divisors is an integer number (31013248926).

Almost surely, 2123113200151 is an apocalyptic number.

123113200151 is a deficient number, since it is larger than the sum of its proper divisors (939795553).

123113200151 is an equidigital number, since it uses as much as digits as its factorization.

123113200151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 939795552.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 123113200151 its reverse (151002311321), we get a palindrome (274115511472).

The spelling of 123113200151 in words is "one hundred twenty-three billion, one hundred thirteen million, two hundred thousand, one hundred fifty-one".

Divisors: 1 131 939795421 123113200151