Base | Representation |
---|---|
bin | 111001010101000100… |
… | …0101111100110101011 |
3 | 102202202222202221212211 |
4 | 1302222020233212223 |
5 | 4004114024100042 |
6 | 132320233345551 |
7 | 11615603340025 |
oct | 1625210574653 |
9 | 382688687784 |
10 | 123113503147 |
11 | 482373aa118 |
12 | 1ba3a5682b7 |
13 | b7c025c61b |
14 | 5d5ca57015 |
15 | 33084ba017 |
hex | 1caa22f9ab |
123113503147 has 2 divisors, whose sum is σ = 123113503148. Its totient is φ = 123113503146.
The previous prime is 123113503031. The next prime is 123113503151. The reversal of 123113503147 is 741305311321.
It is a strong prime.
It is an emirp because it is prime and its reverse (741305311321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123113503147 - 235 = 88753764779 is a prime.
It is not a weakly prime, because it can be changed into another prime (123113503187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61556751573 + 61556751574.
It is an arithmetic number, because the mean of its divisors is an integer number (61556751574).
Almost surely, 2123113503147 is an apocalyptic number.
123113503147 is a deficient number, since it is larger than the sum of its proper divisors (1).
123113503147 is an equidigital number, since it uses as much as digits as its factorization.
123113503147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 123113503147 its reverse (741305311321), we get a palindrome (864418814468).
The spelling of 123113503147 in words is "one hundred twenty-three billion, one hundred thirteen million, five hundred three thousand, one hundred forty-seven".
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