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12312154303132 = 223078038575783
BaseRepresentation
bin1011001100101010010110…
…0101010110101010011100
31121121000211012110200222211
42303022211211112222130
53103210243000200012
642104043044050204
72410344442553065
oct263124545265234
947530735420884
1012312154303132
113a17612143a22
12146a217693964
136b405362a728
14307ca902756c
1516540267e6a7
hexb32a5956a9c

12312154303132 has 6 divisors (see below), whose sum is σ = 21546270030488. Its totient is φ = 6156077151564.

The previous prime is 12312154303121. The next prime is 12312154303147. The reversal of 12312154303132 is 23130345121321.

12312154303132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 12312154303094 and 12312154303103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1539019287888 + ... + 1539019287895.

Almost surely, 212312154303132 is an apocalyptic number.

It is an amenable number.

12312154303132 is a deficient number, since it is larger than the sum of its proper divisors (9234115727356).

12312154303132 is a wasteful number, since it uses less digits than its factorization.

12312154303132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3078038575787 (or 3078038575785 counting only the distinct ones).

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 12312154303132 its reverse (23130345121321), we get a palindrome (35442499424453).

The spelling of 12312154303132 in words is "twelve trillion, three hundred twelve billion, one hundred fifty-four million, three hundred three thousand, one hundred thirty-two".

Divisors: 1 2 4 3078038575783 6156077151566 12312154303132