Base | Representation |
---|---|
bin | 1011001100101101100000… |
… | …0100000101110010101011 |
3 | 1121121010000020002121022001 |
4 | 2303023120010011302223 |
5 | 3103214011303040131 |
6 | 42104303100311431 |
7 | 2410404435340201 |
oct | 263133004056253 |
9 | 47533006077261 |
10 | 12313001221291 |
11 | 3a17a07210091 |
12 | 146a413242577 |
13 | 6b4159c2a034 |
14 | 307d496c7071 |
15 | 165451bc3261 |
hex | b32d8105cab |
12313001221291 has 2 divisors, whose sum is σ = 12313001221292. Its totient is φ = 12313001221290.
The previous prime is 12313001221253. The next prime is 12313001221303. The reversal of 12313001221291 is 19212210031321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313001221291 - 217 = 12313001090219 is a prime.
It is not a weakly prime, because it can be changed into another prime (12313001221091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156500610645 + 6156500610646.
It is an arithmetic number, because the mean of its divisors is an integer number (6156500610646).
Almost surely, 212313001221291 is an apocalyptic number.
12313001221291 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313001221291 is an equidigital number, since it uses as much as digits as its factorization.
12313001221291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 12313001221291 in words is "twelve trillion, three hundred thirteen billion, one million, two hundred twenty-one thousand, two hundred ninety-one".
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