Base | Representation |
---|---|
bin | 1011001100101101100111… |
… | …1101110001100111110011 |
3 | 1121121010002110010020102201 |
4 | 2303023121331301213303 |
5 | 3103214042434321433 |
6 | 42104310200124031 |
7 | 2410405303435102 |
oct | 263133175614763 |
9 | 47533073106381 |
10 | 12313033120243 |
11 | 3a17a23218259 |
12 | 146a421a66617 |
13 | 6b416371845b |
14 | 307d4da2c039 |
15 | 1654548c4a7d |
hex | b32d9f719f3 |
12313033120243 has 2 divisors, whose sum is σ = 12313033120244. Its totient is φ = 12313033120242.
The previous prime is 12313033120237. The next prime is 12313033120253. The reversal of 12313033120243 is 34202133031321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12313033120243 is a prime.
It is a super-2 number, since 2×123130331202432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12313033120253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156516560121 + 6156516560122.
It is an arithmetic number, because the mean of its divisors is an integer number (6156516560122).
Almost surely, 212313033120243 is an apocalyptic number.
12313033120243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313033120243 is an equidigital number, since it uses as much as digits as its factorization.
12313033120243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 12313033120243 its reverse (34202133031321), we get a palindrome (46515166151564).
The spelling of 12313033120243 in words is "twelve trillion, three hundred thirteen billion, thirty-three million, one hundred twenty thousand, two hundred forty-three".
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