Base | Representation |
---|---|
bin | 1011001100101101111010… |
… | …1110111000011100110011 |
3 | 1121121010022000121201221212 |
4 | 2303023132232320130303 |
5 | 3103214223423232011 |
6 | 42104322134310335 |
7 | 2410410264324332 |
oct | 263133656703463 |
9 | 47533260551855 |
10 | 12313113102131 |
11 | 3a17a64386896 |
12 | 146a4447b83ab |
13 | 6b417717050a |
14 | 307d5a4cbd19 |
15 | 16545b92308b |
hex | b32debb8733 |
12313113102131 has 2 divisors, whose sum is σ = 12313113102132. Its totient is φ = 12313113102130.
The previous prime is 12313113102109. The next prime is 12313113102149. The reversal of 12313113102131 is 13120131131321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313113102131 - 26 = 12313113102067 is a prime.
It is a super-2 number, since 2×123131131021312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12313113102097 and 12313113102106.
It is not a weakly prime, because it can be changed into another prime (12313113102181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156556551065 + 6156556551066.
It is an arithmetic number, because the mean of its divisors is an integer number (6156556551066).
Almost surely, 212313113102131 is an apocalyptic number.
12313113102131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313113102131 is an equidigital number, since it uses as much as digits as its factorization.
12313113102131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 12313113102131 its reverse (13120131131321), we get a palindrome (25433244233452).
The spelling of 12313113102131 in words is "twelve trillion, three hundred thirteen billion, one hundred thirteen million, one hundred two thousand, one hundred thirty-one".
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